To find the radius of a semicircle, draw a perpendicular from the center O to chord PQ, which bisects PQ into two equal segments (PM = QM = 14 when PQ = 28). In the right triangle OCM with angles 90° and 45°, the sides OM and CM are equal (both 48). Using the Pythagorean theorem in triangle OPM, the radius OP is calculated as √(48² + 14²) = √(2304 + 196) = √2500 = 50.
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Can you find the radius of the semicircle?本站添加:
Can you find the radius of the semicircle?
Suppose the center of the semicircle is O.
And PQ is 28.
And in any circle if PQ is a chord and O is the center and from the center O if we make a perpendicular on PQ suppose this point is M then it will be called PQ.
So here from point O if we make a perpendicular on PQ suppose this point is M then PM and QM they will be PQ divided by two and PQ is 28 divided by two that will be 14.
So PM is 14 and QM is 14.
And Now in triangle OCM It is O C M This angle is 90° This angle is 45° So this angle It will be 90° - 45° That will be 45° And These two angles are equal That means OM and CM They will be also equal.
And CM is 34 + 14 CM is 34 + 14 That is 48.
So OM It will be also 48.
OM is 48.
And now If we join OP then OP is a radius.
Suppose X.
OP is X.
And in triangle OPM OP is squared it will be OM is squared plus PM is squared.
And OP is X is squared.
OM is 48 is squared.
Plus PM is 14 is squared.
So X is squared is two is squared times 24 is squared plus two is squared times seven is squared.
And X is squared is two is squared times 24 is squared plus seven is squared.
And X is squared is two is squared times 576 plus 49.
And X is squared is two is squared times 625.
So X is squared is 2 is squared.
And 625 is 25 is squared.
So, x is squared is 2 * 25 is squared.
And x is squared is 50 is squared.
That means x it will be 50.
And a radius it is x that will be 50.
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