SSB TGT PCM PYQS ANALYSIS || COORDINATE GEOMETRY PYQS (2019 TO 2025) || #SSB_TGT #RHT2026 #OAVS2026

Added: 2026-06-07

[00:00:00]Hello friends welcome to the competitive YouTube channel to dekhnatu aaj video humein discussion karba coordinate geometry PYQ jo ki apan SSB TGT previous year takar RHT 2022 and humein kah p jothila takar LTR 2024 re jothila tankar o triple sc jo apankar TGT PCM r o exam kothila up jana SSB PCM r o to tar bhi question paper ko humein include kar to e humein basically discuss kar se sab question paper ko theek to aaj humein chapter ko discussion kar ch coordinate geometry to previous humein already discussed kar sarchha ka ko set theory ko already discussed kar sarchha aur ta par apan ko relation function ko discussion kar sarchha calculus ko discussion kar sarchha quadratic equation ko humein discussion kar sarchha jo apan mane dekhi nath tar PYQs r solution video gu ko j ki dekh pve playlist upload a humro channel re to playlist ko jave SSB TGT PYQs re up dekh se video gu ko pai j thik achhi so topic wise humein at PYQs ko discussion kar chhati to se series re aaj humein discussion karba ka coordinate geometry ko discussion karba to coordinate geometry jo apne me dekhbe atre basicly apnekar do teenta topic pura mix th kemti pratham ho apnekar basic of coordinate geometry jo three straight line aati padtaau thik distance formula padtaau area of ​​the triangle padtaau par second up circle part to circle part ho up and other topic jo ki coordinate geometry includ karik section up dekhne up three topic includ ho parabola ho ellipse g hyperbola so aaj humein kaun kar dekhhu e video re humein discussion karba apne basic of coordinate geometry j bhi question a straight line parant second part re humein discussion karba circle aur conic section ra discussion I hope you guys will discuss many questions which we have to solve as it is difficult because this video is very long so let us start by completing the data part so first let us start with some important topic which is to help us solve the question as per the first step we have to take the data point given so suppose the point given is x1 y1 and the point is x2 y2 so friends the slope should be written as m and the slope should be y2 - y1 / x2 - x1 and our slope formula is y2 and next we will take out the equation of the straight line in its place and let us take the slope of m and the point is passed to it If we have given a correct equation of the straight line then we have to write the equation of the straight line. If we take y - y1 and pass a point and put the slope m then the equation becomes y - y1 = m * x - x1 and the equation of the straight line becomes y - y1 = m * x - x1 so the equation of the straight line becomes y - y1 = m * x - x1 so the slope of the straight line becomes y - y1 = m * x - x1 so the equation of the straight line becomes y - y1 = m * x - x1 so the equation of the straight line becomes y - y1 = m * x - x1 so the equation of the straight line becomes y - y1 = m * x - x1 so the equation of the straight line becomes y - y1 = m * x - x1 so the equation of the straight line becomes y - y1 = m * x - x1 so the area of ​​the triangle is the area of ​​the triangle which is the area of ​​the triangle and the area of ​​the triangle is the area of ​​the triangle which is the length of the triangle and the length of the triangle is the length of the triangle and the area... If we calculate the area of ​​the triangle then the area of ​​the triangle will be calculated as 1/2 * determinant and if the area of ​​the triangle is zero then the correct case is that if three points are collinear then it is a collinear method which can be used to solve any question. If the vertex of the triangle is equal to the vertex of the triangle then it is a collinear method which can be used to solve any question. If the vertex of the triangle is equal to the vertex of the triangle then it is a collinear method which can be used to solve any question. If we divide the triangle by the median of the triangle and then draw the triangle's median. If this median intersects the point, then the centroid and the coordinate of the triangle are given by g. So, the centroid and the coordinate of the triangle are given by g. And g = 1 + 2 + 3 / 3 and the y coordinate is y1 + y2 + y3 / 3 and the zero... If the point p is 4 then the z coordinate is from the line joining the point p to the x coordinate then the line upar g point is from the p point and the x coordinate is given then the line upar g point is drawn graphically so suppose this one is a line segment at which the point is given by 2 1 and at which the other point is given by 5 1 -2 a line upar g P point is drawn then the x coordinate is from the y coordinate then the z coordinate is not given and hence the z coordinate is not given and hence the z coordinate is not given and hence the z coordinate is not given and hence the z coordinate is not given and hence the z coordinate is not given and hence the line segment at which the p point is drawn is divided by the ratio of the first of all the middle points If we calculate the ratio then find out the ratio of pi to z then basically find out the z coordinate then first we have to calculate the ratio by looking at the x coordinate point write to 2 and four then four and five are the difference of 1 and one then we have to basically calculate the ratio by looking at the x coordinate point write to 2 and four then four and five are the difference of 1 and one then we have to calculate the ratio by looking at the x coordinate point write to 2 and four then four and five are the difference of 1 and one then ratio how many up to 2 and 1 then we have to calculate the ratio by looking at the x coordinate point write to 2 and four then four and five are the difference of 1 and one... If the y coordinate given is 1/2 then the y coordinate given is 1/2 and... If we read the area of ​​the full circle and add the three vertices then we write 1/2 determinant of it -3 0 3 0 0 k and then you can write 1 1 so if you see the value of this half then we will see that it is equal to 18 piva and at the same time we will calculate the value of the determinant so we can calculate the determinant by choosing the right row or right column and if we get zero then we will see zero at zero at zero a sorry zero at zero a so we can see the second column up and open the second column against which we will open the determinant so we can quickly open the sign of this minus which is plus or minus which is plus or minus so we will write the same as minus k 18 = 18 and if the value of 1 is 3 then the line segment joining the point - 6 * 1 is -3 and then the line segment joining the point - 3 * 1 is 3 then this = 18 then we have to solve the problem by adding -6 and -k so that means we have 6k = 18 and if the value of 1 is 3 then the option we have to look at is k value of 3 then the option we have to look at is k value of 3 then the option we have to look at is the correct answer then the next question we have to look at is 3 and then the SSB question is also the correct answer then we have to read the question carefully so the hard body question is not easy to read so you can miss the data in the question and answer section so the question is in what ratio the line segment joining the point - 6 15 3 5 divided by the y axis so at to the y axis the line segment a which is the point If we join the line segment along the y axis and divide it by the ratio then divide by the technique and learn the question from the second solution. If we learn the technique and solve the question from the second solution then we can see that -6 15 eta is the point and if we do n't know at the B point then we can see that the B point is 3 5 and the B point is 3 5 and if we know the Y axis then we can see that the X coordinate is obviously zero so the X coordinate is zero and the Y coordinate is y written down so we have the x coordinate given so the x coordinate difference is -6 eta is zero and the three difference is 6 units and the three difference is 3 units and if we divide it by the ratio then we have to look at 2 1 then 2 1 is option C Re to option one hero sorry option C yaar correct answer thik achhi a [nasal sound] next question to SSB TET three question thila jo humein kar se RST 2023 ro question to RST 2023 re ko question pachla dekhantu find the equation of the line which makes intercept -3 and end two on the x axis and y axis respectively so line row equation matlab batantu jo tha ki x axis intercept ban -3 and y axis intercept ban 2 unit intercept mane ko sir dekhantu apan ko simple bhau intercept mane ko eta jo humein do kar dele coordinate axis do kar dele eta ho apan x axis eta ho apan y axis se kahla ki apan ko x intercept ho -3 -3 mane se x axis ko -3 0 re cut cut kar ch thik achhi a ho basically intercept kab So, if we have y intercept then we have to cut the y axis at 0.2. So to get the intercept we need to find the equation of the straight line. So, if we have given the data point then first we have to place the point near the intersection and then calculate the slope by doing this. So, the slope is y2 - y1 which is 2 - 0 / x2 - x1 = 0 -3. So this 2/3 slope is 1. So, if we have y intercept then we have to raise the point to -3.0. So the equation is y - y1 which is 0 = 2/3 * x - x1 so x1 = -3 which is = +3. So, how many y = 2/3 x + 3 multiply by 3y and multiply by 2x If we subtract 2x and 6 then we can write 2x - 3y + 6 = 0 then we can write the answer ok to give option c and another technique if we don't want to find any intercept then the formula of intercept equation is x/a + y / b = c or if we put equal to c in its place then write it ok to write equal to 1 [nasal sound] then we can write the intercept form of equation so if we put -3 in its place then put -3 in its place and y intercept in its place then put it in b then look at x/ -3y/2 = 1 or solve the LCM of -6 2x a - 3y = 1 so 2x - 3y = -6 solve it 2x - 3y + 6 = 0 so see from option C the same equation is given, okay so there is no need for tension, you can solve the question by winning but the next question is given find the distance between the parallel lines from here tell me to find the parallel line, find the parallel line and calculate the distance, see find the parallel line and calculate the distance, it is very simple, well the parallel line is written first, tell me see ax + by + c1 = 0 and it is written ax + by + c2 = zero so here [nasal sound] do your question somewhere write this ax by, write this ax by, what is the equation If we divide the parallel line by the difference of the two parts then the difference of the two parts is the same as the difference of the two parts. If we divide the parallel line by the difference of the two parts then the difference of the two parts is the same as the difference of the two parts. If we divide the parallel line by the difference of the two parts then the difference of the two parts is the same as the difference of the two parts. So, if we divide the distance by the distance formula then the distance formula is c2 - c1 and the distance formula is c1 + b2 and the difference of the two parts is the same as the difference of the two parts. If a and b are equal then directly we write the square a² + b² and then the question is given by 3x - 4y + 7 and also Diya 3x - 4y + 5 diya to c1 and c2 ko achi halkachi to distance kon dekhantu 7 - 5 mat dochi and kaun kar square 3 rho² + -4 rho² to ke to and 3 rho² + 4² ke hoye 5 to humein kaise par right answer 2/5 ko option c so option c ho correct answar toh bhai jahan bhaar mothi aap ko sansthan se slash bujha pad to j questions sansthan aap ko bujha pad aproaches aap ko bhagwa dena aap me video ko like karntu aur channel ko j subscribe kar ntu pdf jo apne paya p jach video description telegram group link a se join hi jaantu jaan bhi aap ko youtube video milbo tar pdf aap ko se telegram group re mil thik achhi e chalantu java humein next question ko so next question kaun diya distance of the point -6 8 from the origin origin to If the distance is equal to the horizontal then the distance formula is 0 then x1 - x2² is equal to -6 and x2 is equal to zero then we can see -6 - 0² and y1 - y2² that is 8 - 0² rootvar so ita 6² + 8 rootvar = 36 + 64 rootvar is equal to 100 rootvar and 100 rootvar is equal to 10 so 10 bhai correct answer means option C is thik ye question gu 2022 question guji type question thila up me dekhi ki p question level gu ki 2023 re keti question pathila SSB re keti question pathila LTR k question pathila 2022 re keti question pathila up se ko Compare and solve it, okay and if you want to know the distance of the point from the origin, okay, if you want to know the distance of the point from the origin, then the distance is the square root of a² + b², so we will directly get 6² + 8², then we will also get the next question, so let's see the next question, the distance of the point 2 3 from the x axis, so solve this type of question, okay, solve it carefully, because there are more chances of mistake in this easy question, so if you have any doubt, then draw the first diagram, so draw the y axis, and the x axis, and the y axis, and the point up to 2 3, so we will draw the perpendicular up to 20 units and then If we draw a perpendicular then the distance from the x-axis is 3 units... y-coordinate is 3 units then the distance from the x-axis is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-axis is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-axis is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-axis is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-axis is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-axis is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-axis is 3 units then the distance from the y-coordinate is 3 units then the distance from the y-axis is 3 units then the distance from the y-coordinate is If we consider the determinant of the determinant as zero then it is collinear and if we consider the method then if we consider the determinant as zero then it is collinear and if we consider the point A then it is not collinear then it is collinear and if we consider the point C then it is collinear and if we consider the line A then it is parallel and if we consider the line B then it is parallel and if we consider the line C then it is parallel and if we consider the line D then it is parallel and if we consider the line D then it is parallel and if we consider the line D then it is parallel and if we consider the line D then it is parallel and if we consider the line D then it is -1... So first we have to calculate the slope of the point and then we have to compare the slope of the slope and that is equal to the value of the slope and then we have to calculate the k value. So first we have to calculate the slope of the slope of m1. So m1 has to be divided by 2k + 3 - 2k. Then we have to calculate the slope of the slope. If we calculate the slope of m1 then we have to calculate the slope of m2. If we calculate the slope of m1 then we have to calculate the slope of m2. If we calculate the slope of m1 then we have to calculate the slope of m2. If we calculate the slope of m1 then we have to calculate the slope of m2. If we calculate the slope of m2 then we have to calculate the slope of m2. If we calculate the slope of m1 then we have to calculate the slope of m2. If we calculate the slope of m1 then we have to calculate the slope of m2. If we calculate the slope of m2 then we have to calculate the slope of m1. If we calculate the slope of m1 then we have to calculate the slope of m2... If the denominator is same then cancel it out and then cancel it out. So 3 = 3k - 3 but the hypotenuse is 3k = 6 and k = 2 then this is the correct answer i.e. option B is the correct answer so we have to compare the slopes and check the collinearity.

[00:21:53]So the next question is given by next question, then the distance of the point is -2.5 from the y axis. So the distance left on the y axis is -2 [nasal sound] so this is the correct answer so option C is the correct answer so next question is given by next question, then the coordinate of the centroid of a triangle with the vertices 0 3a 0 and 0 3b If we add x1 + x2 + x3 / 3 y1 + y2 + y3 / 3 then x1 is 0 x2 is 3 x3 is 0 then if we add 0 + 3a + 0 / 3 then write the second term 0 + 0 + 3b / 3 then our value is 0 then our value is basically 3a / 3 and 3b / 3 so if we subtract 3 then a = 0 and b = 0 then a = 0 and b = 0 then a = 0 and b = 0 then we calculate the centroid coordinate and next question is to find the area in square units of the triangle with the vertices 0 b a 0 and 0 then from the triangle with the vertices 0 b a 0 and 0 then from the vertices of the triangle we calculate the area of ​​the triangle so the area of ​​the triangle is what is the determinant of the triangle. First we calculate 1/2 a 0 b 1 If we add 0 1 to the 0 0 then we can delete the row and column so that it is 0 - ab. So basically, we get the value of 1/2 1/2 * -ab equal to ab / 2 ab / 2 means 0.5ab.

[00:24:15]We get the area of ​​the triangle which is also negative 0.5ab.

[00:24:19]Yaar right answer is option B ok good minus no doubt but apan ko area ke bhi negative asib a gu method aur gu method up ko kar point plot kar de point hi sam akchi rakhantu very easily question solve pl 0 means up is the origin point given a 0 means 8 given a 0 means distance be a unit and guta diya 0 b means a point ok j distance be b unit jo apan a ko join de to kar a so basically eta a right angle triangle milache right angle triangle up base ho a height ho b fulla ho 1/2 * ab which equals ab / 2 1/2 * base * height ok so eta ab / 2 which is option B correct answer a next question so next question ko diya dekhantu the triangle formed by a non collinear point -5 6 -4 -2 and 7 5 is so uso triangle banau If you are not preparing for the three point then type triangle like equilateral, isosceles, scalene and right angle triangle. So first we have to calculate the side and distance of the three point. Second we have to calculate the side and distance of the three point. Third we have to calculate the three point distance. Then we have to calculate the distance of the three point. Triangle type triangle is to calculate the distance of the three point. If you are looking for -2 - 6² and plus -4 + 5² then root of 8² - 6² and 1 root of that is equal to 69 root of 8² - 4² and 1 root of that is equal to 69 root of 8² - 4² and 7 + 4² root of that is equal to 7² 49 and 7 + 4 is 11² 121 Add root of 170 to 170 root of 170. Okay, so next we see -5 6 and 75. So we see 5 - 6 6 and 7 + 5².

[00:26:47]So we add basically 1 and 12 means 144. So we can say root of 170. We see that our angle is a triangle, which is a type of triangle and its sides are equal. So obviously not the isosceles's quota side is equal.

[00:27:06]If the scale is on the right, then the scale is obviously right.

[00:27:10]Next question is whether it is a right angle or not. If it is a right angle, then the Pythagoras condition needs to be satisfied. If p² + b² = h² is 170, then it is obviously not right. If you add 69 and 145, you get 170, then it is also satisfied. If the answer is correct, then it is a scalene triangle. So check me up.

[00:27:35]Next question is what is the length of the median drawn through the vertex 7 - 3 in the triangle having the vertices 7 - 3, 5, 3 and 3 - 1. We have a triangle and three vertices. These three vertices are given. So, from these vertices, we have the median drawn through the opposite side. From these three vertices, we have the median and the length. Look, the question is not any simple question, good triangle up, suppose if you don't want to see, then suppose you have triangle eta hala point, I have 7 - 3 eta hala point, I have 5 3 and eta point is I have 3 - 1 then what is the median, that is, a point, I have to find the median, so what is the median, obviously bisect the opposite side, so what is the bisect, see what is the coordinate, a no, a d only, so d coordinate is 5 + 3 / 2 which is 2 / 5 + 3 8 / 2 4 3 - 1 3 - 1 2 2 / 2 row coordinate 1 so 4 1 mid point ke calculate kar jani thave, so my friend mid point calculate kar b and 0 ok, good if you have to calculate the row distance, simple and what is it, then see 1 + 3 row² is equal to 4 - 7² or root over to 4 row² is equal to 16 and then option B is equal to three row² 9 so 16 + 9 means 25 root of 25 root of five units so option B is correct answer I hope you can answer it on the same path so next question is what is the given equation of a straight line can be expressed by using straight line and equation ko kemati express kara jaye obviously linear equation hi apan ko straight line equation hi tha and quadratic equation ko parabola hi cubic equation to random banbo thik by quadratic fourth degree so seta ki kahne ki ko type figure bani to linear equation hi apan ko straight line bani ta par next question asila ki distance of the point ABC from the YZ plane so dekho YZ plane jemati apan ko sethi diyala question Distance of the point from the X axis Y axis type question can also be solved by taking the X coordinate up the distance from the Y axis, so do it but the right answer option is A, which is negative distance from the point. If we write it, then try to solve it.

[00:30:07]Suppose we have to take the x coordinate, i.e., the y coordinate, and at that point, we have to take the z coordinate, so from this place we have to take the x coordinate, i.e., the y coordinate, and the z coordinate, so from this place we have to take the a b c point given by the... If the x coordinate of a point is zero then the y-z coordinate of a point is zero then the x coordinate of a point is zero then the z coordinate of a point is zero then the distance between a point and a is calculated as a - 0² b - b means 0 c - c means 0 or the root of a point is a² then the root of a point is basically a point which is equal to the distance from the point 2 - 5 and - 2 9 then the right answer is given as the right answer is given as the next question is which of the given points in the x axis is equal to the distance from the point 2 - 5 and - 2 9 then the x axis ray is a point which is equal to the distance from the point 2 - 5 and - 2 9 then the x axis ray is a point which is equal to the distance from the point 2 - 5 and - 2 9 then the y coordinate of a point is obviously zero then the point is not a 0 If there is any equal distance from a then a point and a point distance should be calculated so see -5 - 0² means -5² and ab 2 - a² see friend calculate distance a 0 then 9² and a -2 - a² root over see so squaring both sides so root h so how much do we have to calculate up to 4 + a² - 4a okay and we have 8a - 2² 4 - a² a² now up to 2 * 2 * a that is = 4a okay then a² is divided by 4a then a² is divided by 4a so we have to calculate 8a equal to 25 - 81 25 - 81 so you can see 11 5 then 6 and 7 2 means 56 and a value 7 so a sorry a minus then -7o then -7 8 ho to point up to -7 0 Okay, next question, see the distance of the point 1 2 from the line joining the point -1 3 and 4 2 so the distance of the point from the line joining the point this and this so we have to say that at a point joining us draw a line so line r o point distance bacha so basically first we have to see the equation of the line ka kya padbo Okay, so equation of the line we have to calculate the slope yaar so slope of m = up ah 2 - 3 2 - 3/4 -1 so 4 + 1 = -1/5 slope of the equation of the straight line kaun see so y - 3 -1/5 x + 1 solve that 5y - 15 = -x - 1 x and 1 put x + 5y and up -14 = 0 so we have to find the equation of the straight line Equation of the straight line usko kaun kar distance calculate kar 1 2 ke ho to distance formula ho simple up ko dekho ye jo apan ko dekho equation question equation x and y pave ko 1 2 pake toh mane 1 + 52 -4 and mod divided by a² + b² a ho x coefficient b ho 5 coefficient mane y rho coefficient so 1 rho² + 5² so how much look 1 + 10 and that is 11 - 14 hi up is -3 -3 mod is +3 and divided by 26 so 3 / 26 koti diya option b re diya so option b is bhaiya question correct answer ok good so question date ke bhase p type question ko ka blunder chances bahut ach thaaye par asantu next question ko diya from the focus of the parabola y² = 32x a line of If the slope of a line is given by a parabola then the equation of the line passing through its focus is given by the slope of the line. So the first parabola equation is given by y² = 32x so if the point is given by a 32 then the focus is given by 4a = 32 and the standard equation of the parabola is given by y² = 4ax so if the point is given by a 32 then the focus is given by 4a = 32 and the standard equation of the parabola is given by y² = 4ax so if the point is given by a 32 then the focus is given by 4a so if the point is given by a 32 then the focus is given by 8 and the focus is given by 8 then the focus is given by 8 and the focus is given by 8 then the focus is given by 8 and the slope is given by 8 then the equation of the straight line is given by y - 0 = slope * x - 8 so if the point is given by a 32 then the standard equation of the parabola is given by y² = 4ax y = x - 8 y = x - 8 kothi achhi option b re to option b is correct answer tension kisi darkar nahi jo apan ko parabola ya phir an equation agar problem ho ke na next jo part parts se part re humein circle aur conic section jit bhi question a tako humein complete kara sahi jhan ko parabola ellipse hyperbola jahan bhi basic definitions a equation a se ko apan ko kahi devi se ok achhi to tension kisi darkar nahi next dekho question kaun pachila a triangle is formed by the point 5 8 2 7 and the point where the line x = 3 and 2x + 3y = 12 intersect se kochi triangle ban chhati jo ki a point a point aur ata jo dekho straight line ata straight line intersection point a to teenta point ko nahi ki kochi triangle ban ho to se triangle r ko na centroid coordinate ke se pchla to pratham hume ko kar pubg Calculate the third point. If we calculate the third point then it means this point is the intersection point of the line. If we calculate x = 3 then we have to calculate the second equation of the line x = 3 then it is 2 * 3 + 3y = 12 so 3y is equal to 6y is equal to 2y then we have to calculate the point 3 + 2 and another point which point we have to calculate 5 8 and 2 7 directly then we have to calculate the center coordinate. If we add 3 + 5 8 + 2 10 then 10/3 = 10/3 = 10/3 = 10/3 then option D is the right answer. If we write 2 + 8 then 10 10 + 7 is 17/3 then option D is the right answer but next question is where is the point 1 - 1 -1/2 1/2 and 1/2 are the vertices of so before that 8 minute point which achhi mane kaha vertices hai ichi katha nahi athi directly apan ko kar pab ko distance calculate kar pab so skip up the question up niz kar kna question kisi kar nahi just khali distance bahar kar asantu next question ko so dekhantu next question kaun diya the equation x² + y² = 4 is solved for all integral values of x and y so this equation achhi eta sab xy p solve kara hai to sabu xy p solve kara hai to humein xy point gu ko p obviously to se point gu ko j ko hai na plane upar plot kara hai jo figir banla se figure se pala area khchi akchi ok so first of all equation dekhi kaun laga equation kahan equation x² + y² = r² ok x² + y² = r² j apan ko jaane wala problem ho tension zarkar nahi ata ho circle equation ye circle equation re r ho apan ko radius thik achi to a r² place ke four achi to r² = 4 to r ke to asbo jo apan ko radius to milala then area of ​​the circle area of ​​the circle ho πr² so π * r² is 4 to 4π hee apan ko correct answer 4π kothi ho option b re to option b right answer chalantu to ko thila apan 2022 apan 2021 2019 jo prashan thila tako humein discussion kar le e jo prashan gu se ho ltr question gu ltr question gu ko humein dekhva dekhantu first prashan humein ko diyala the equation of the normal to the curve y = e power x at x = 0 So first we have to calculate the normal line equation by taking out a curve and then taking out the point and passing it to the key we have to draw the normal line. So let us put x to zero and y value to the power 0 equals 1 so x is zero and y is one so that means 0 is 1 up point x is zero and y value is one so that means point is 0 is 1 so we have to calculate the normal line equation by taking out the slope and slope of the curve so we have to take the derivative of the equation of the curve and take the derivative with respect to x so dy / dx is equal to x and the derivative to the power x is equal to so the slope of the tangent line is equal to m1. If we put zero in place of x then the slope of the tangent will be one and we have to know that the tangent line and the normal line, the slope product will be -1, that is, if the tangent line, the normal line is perpendicular then the normal line slope will be m2, otherwise m2 will have the value -1, so if m1 and m2 are equal to -1 and m1 and m2 will obviously be -1, okay, so if we calculate the equation then the equation will be y - 1 = slope, then x - 0, so y - 1 = -x, now if we put x then we have to y + x - 1 = 0, y + x - 1 = 0, so let's see y + x - 1 = 0, okay, if we have given m, then let's see y = -x - 1 option If option A is correct then [nasal sound] then next question is given by [nasal sound] then next question is given by the equation of the line passing through the point G line J point ko pass kar jaun J ki x intercept jo asuchi se twice na y intercept twice ho jo question kar apan ko difficulties koi nahi tension jarakar nahi ok question ko solve kar technique dekho to ke solve kara ho jaldi solve kar p lengthhi kisi nahi se kochi line type point ko pass kar jo point ko pass kar ta mane jahan bhi option se option satisfai kar to wahi point ko ok ki dekho to ko satisfai karchi e jo pake deli first re to ko three 3 + 2 * -4 ko -5 mil chahiye milu chahiye second dekho 3 + minus minus plus ab 8 3 + 8 5 mil mini so kala par second third dekhontu ela 3 - 4 2 * 4 that If 8 is given then how much is -5 and if we get 5 then how much is -5 and if we get 5 then how much is the right answer then option A is completely correct and option D is the right answer then option B is completely correct and option C is completely correct and so [nasal sound] up verify If option A is selected then option D is to be ticked.

[00:44:09]Next question is which of the following statements is true about the slope of the line parallel and perpendicular to the y axis? If the line is parallel to the y axis then the slope of the line parallel to the y axis is zero. Suppose this one is x axis then this one is y axis slope full. If tan theta is 90° then tan theta is 90 ° and tan 90 is 90° then sin 90 / cos 90 is infinite then the slope of the parallel line is infinite. The slope of the line parallel to the y axis is zero. If both are parallel then they are not equal to each other and if neither is equal to each other then the correct answer is option B then the parallel line and the slope of this is infinite then the perpendicular line and the slope of this is zero then the y axis is perpendicular to the theta then the x axis is 0° then the angle formed by this is 0° then tan 0 is tan 0 then it is perpendicular to the y axis is zero then option B is the correct answer.

[00:45:29]Know the next question which is the area of ​​the triangle formed by the x axis y axis and the line this is ok ok eta is the last question so let's solve the last question very easily so eta is our x axis eta is our y axis and angle line ye line up ko kar pratham to x ko zero karantu x ko zero pibe 2y = 4 pb then y = 2 so point kola 0 2 hala point par y ko zero karant y ko zero pi j x value 4 p which is 4 0 ok achhi a just kahn akchi hum ko basically x axis a line y axis ye line ye jo triangle bani triangle area kaalte kar so area ko eta jetu right angle triangle ho right angle triangle area ke 1/2 * base base ho 4 units height ho 2 units to 2 units ktila answer fo so right answer humein kab option c hai yaar correct answer so today video humein coordinate geometry jitni bhi question thila up almost 25 question thila 25 question ko humein discussion ko jo coordinate geometry basic and straight line up base thila ok So next class re humein circle aur conex section ko discus karba so if you like this series bhagwa aaj video bhagwa then video ko like karnatu channel ko subscribe karnatu aur pdf pe chahantu video description telegram group link a se jaake apne mane kaun kar pave join kar pave aur se pdf download kar pave so dekha next video re se parant jai jagannath thank you