This video demonstrates how to simplify complex algebraic expressions without a calculator by using the conjugate method to rationalize denominators and applying index laws. The process involves multiplying the numerator and denominator by the conjugate of the denominator to eliminate radicals, then simplifying using algebraic identities like the difference of squares (a² - b²) and binomial expansion (a + b)² = a² + 2ab + b². The example shows simplifying 1/(2√3 - 3)⁶ step-by-step, transforming it into (7 + 4√3)³/27 through systematic application of these mathematical techniques.
深度探索
先修知识
- 暂无数据。
后续步骤
- 暂无数据。
深度探索
Olympiad Mathematics Trick | No use of calculator.本站添加:
Okay, so what do you think this is equal to?
Mind you, we are not to use calculator here.
We're going to see how we can simplify what we have.
This is 1 over 2 the square root of 3 minus 3.
This is raised to the power of 6.
So, how do we simplify this?
First of all, we're going to deal with what we have in the bracket.
Remember what we call the conjugate, right?
So, we have 1 over 2 square root of 3 minus 3 then multiply this by the conjugate, which is the this denominator, but here we're going to have um addition.
So, we have 2 square root of 3 plus 3 over 2 square root of 3 plus 3.
So, whatever we have here is still raised to the power of um 6.
Now, we're going to multiply so that the denom- the numerator will be 1 times that, that will be the same thing, 2 root 3 plus 3.
This is all over the denominator we have um 2 root 3 minus 3 to multiply 2 root 3 plus 3.
So, the whole of this is still raised to the power of 6.
And what can you see from the denominator here? We have difference of two squares.
Because a minus b multiplied by a plus b is the same thing as a squared minus b squared.
And that's what we have here. So, our a now is 2 root 3 and our b is 3.
So, let's express this in this form.
Okay, let me remove this.
So, that we can have 2 root 3 plus 3 right?
Divided by here, we have 2 root 3 to the power of 2 then minus 3 to the power of 2.
Remember that this is still to the power of 6.
Interesting, right?
So, we take a step forward and we get to square root of 3 plus 3.
This is all over here. We have um You know, this is 2 to the power of 2, right? So, we have 4 multiplied by this can take this out now.
So, we have 3. Then we have minus 3 squared, which is 9.
Everything here is still raised to the power of 6.
You know, I've not really touched the the power, right?
So, from here we have 2 root 3 plus 3 over here, we have 4 times 3, that is 12.
12 minus 3, 12 minus 9 is 3.
So, this is now raised to the power of 6.
Okay, this is raised to the power of 6.
Now, see what we can do from here?
Okay, so from here now You know we can write this as two root three over three plus three over three right?
Yes, this is the same thing.
And three into three is one.
Meaning that we have two root three over three plus one is raised to the power of two.
Of six rather.
But we can even break the power down.
Let's break the power down.
So that we have two right?
root three over two is over three then plus one This is raised to the power of two plus two plus two.
This will give us six.
And from one of the laws of indices you know that a to the power m plus n is the same thing as a to the power m times a to the power of n.
I hope you remember that right?
Okay, so if you do we're going to write this as two over three root three plus one This is raised to the power of two.
Then multiply by the same thing two over three root three plus one raised to the second two. Why is it multiplication between the bases?
Because it's addition.
You know, among the powers right?
So here we have two over three root three plus one and this is still raised to the power of two.
Okay.
Sorry, I wrote that out of sight, right?
Okay. So, what we're going to do now is to expand one of this. Let's expand one of this.
So, we know that a plus b to the power of two is same thing as a squared plus two a b and plus b squared, if you can remember.
So, the first term here now is going to be a squared, which will be two over three root three. That's our a.
Then this will be squared.
Then we have plus two times a. A is this.
two root three over two then multiply by b. Our b is what?
B is one, so we multiply this by one.
Then plus here we have b squared, which will be one squared.
So, whatever we have from here now is what should be is what this represents. Like the whole of this squared. That's what this represents.
Now, let's simplify this.
Okay, so here we have two um two squares, that is four over three squared, that is nine.
Then this can cancel this, so we multiply this by three.
Then we have plus we go over to this.
Oh, sorry. No, this is three.
This is three here, right?
So, if we open this, we have two times two, that is four over over three, then we have um root three.
And this is plus one.
Now, to still go on from here, what do we do? This is 12 over nine plus here we have four over three root three then we have plus one.
By the way, 12 over nine, we can reduce it.
We can reduce it and we get four over three.
Okay, three into itself one, three into nine is three.
So, this is what we have.
Then, we find the LCM.
The LCM of all of this is three.
So, that means we have three here.
And we do this.
Three divided by three is one, so here we're going to have four.
Then, three divided by this three is one, then here we have four root three.
Then, plus three divided by Okay, just multiply three by one and that's is three.
So, from here from here, see what we're going to have.
We can add these and these, so we get seven.
Then, we have plus four root three. Okay, I hope we can see. You know what?
Let me write this better.
Okay, so this plus this is going to be seven and we have plus plus four root three.
This is all over three.
Okay, so this is what we have in the first bracket. And we're having this in two places, in three places.
Yes, we're having this in three places. So, this means that whatever we have now can be raised to the power of three.
Okay, you can open the bracket and you have 7 + 4 root 3 to the power of 3 Okay, and everything will be over 3 to the power of 3, which is 27.
Right? So, what are we saying now?
We are saying that 1 over 2 root 3 minus 3 to the power of 6 is the same as 7 + 4 root 3 to the power of 3 all over 27. So, the two of them are the same thing from what we have been able to simplify.
Now, if you want to go on with this, we can still simplify this.
But, for the sake of time, we stop here.
相关推荐
A Number Plus 5 Is 12
MathGirlTutor
101 views•2026-06-03
How to solve this radicals? #radicals #maths #mathematics #mathreview
MsRosette
851 views•2026-06-02
Olympiad Mathematics | Indian | Can You Solve This One?
PhilCoolMath
650 views•2026-06-03
H2 Math June Holiday 2026 Intensive Revision | H2 Math Tuition by Achevas #singaporemath #h2math
AchevasTV
304 views•2026-06-01
Escaping the Fog
LogicLemurGaming
760 views•2026-06-03
slick TMUA geometry!
JPiMaths
109 views•2026-06-04
Edexcel IAL S2 Statistics June 2025 - Complete Paper Walkthrough | WST02/01
Math_Mind_1
140 views•2026-06-03
Can You Solve This Simple Math Problem?
Math_Joy
11K views•2026-06-04











