MHT-CET 2027 | Thermodynamics JEE & NEET PYQs | Can You Solve Them? |

[00:00:04]Hello, welcome to Matrix Science Academy. Today, I want to solve questions on the topic of thermodynamics. Questions from JE, NEET and CET. Yesterday, I had solved the 2026 CET, but today I took questions from the previous CET, which were good. Because there are a lot of repetitions in CET. So if it's the same question, I didn't take it, but I took new questions. So, we will solve the questions of CT, we will solve them properly, we have selected all the questions of different entrance exams, which match the syllabus of CET. Since there is little time today, I have reduced the number of questions.

[00:00:44]Total 15 questions. We are going to solve 15.

[00:00:48]Okay, there are 15 questions in total.

[00:00:51]Let's start with question number one. Let's start with question number one.

[00:00:58]First question.

[00:01:01]You can also solve it. You can put the answer in the chat box. Okay, let's start with the first question. The first question is: Initial pressure volume of monoatomic gas. Given a monoatomic gas and its initial pressure volume P, what will be the change in internal energy in an adiabatic process? What will be the change in internal energy if the final volume is 27 times Now let's see the change in internal energy. The process is adiabatic and there is a zero in an adiabatic process. We know that the formula of internal energy is the same for any process, whether it is isothermal, isobaric, adiabatic or isothermal. The formula of internal energy is the same.

[00:01:45]AC delta is the only formula. And this formula is NC delta.

[00:01:54]We will simplify the formula further. We will take the rest of the versions as f times A delta. The third version is A delta minus Gamma.

[00:02:06]And the fourth version, which is going to come in handy here, is the first time it is the delta of P. That's the formula that will be applied here. Here I just have to figure out how much change in P was before. How much was the change in P before? The previous pressure was P. The previous pressure was P. Initially, now what finally happened? Finally, the volume became 27 times the pressure. How much has happened I have to calculate using the adiabatic condition it is like this Pma constant so pv re gamma p2 27 time has happened 27 time has passed re gamma here re gamma and gamma will cancel only 27 re gamma will remain but gamma is monoatomic so it is 5/3 so here it will be 5/3 and if I do re 5/3 then cube root of 27 is 3 f I have to do so how much p2 will come know why p2 will come p a 3 f as p2 will come so I put p2 here you final is initial p what will final p get then final p get p at re f * 27V 27 is cube of 3 cube of 3 and 35 f will remain 3 square so PV is not happening so delta p what will come know why p final final minus p initial initial av gamma minus one gamma pa bati Minus one saw karayach p final final ch answer coming p by na p final final answer what p by na minus minus p initial initial answer p is upon f bath minus one atto bath if it goes beyond nine then one pv minusson p is minus a pv upon upon this is to by th one thatto one fo minus four by thti as answer coming minus four byth TV live started now do you hear sound everyone tell me is the audio video clear in the chat box?

[00:04:55]Okay, good, so the first question was a little tough, which is the mains 8 April, two or three months, there is still question 26 2026, which is the question now, this question requires knowledge of CET, but I wanted to understand a little systematically what to do.

[00:05:12]Okay, it was adiabatic expansion, so how did I always calculate adiabatic expansion?

[00:05:19]How much was the final pressure? The final pressure P was coming from the bath and the final pressure P was coming from the bath. Then I used the formula for the change of internal energy.

[00:05:29]Because I have one, two, three, but what is the use of these?

[00:05:34]I want the temperature without the temperature. I want the temperature with P, so the answer is delta. Okay, now I want you to solve the next question number two. This is suitable for everyone.

[00:05:46]Even if the question is level, tell me its board number.

[00:05:50]What will be the answer? In the chat box, question number two, A B C card, tell me quickly in the chat box. I have put a poll.

[00:06:17]Heat supplied to diatomic gas at constant pressure. We remember the constant pressure directly. What is the shortcut to divide it in this ratio? It is diatomic rigid or non- rigid. Nothing is given. But if it is rigid, if it is non- rigid, if it is rigid, then it is non-rigid, then it is 72. There are no both options here. If it is f, then the answer is delta. Very good. Very good.

[00:06:48]What is the matter? The next question is very easy now.

[00:06:53]This is a numerical question. There are no options for this. You have to solve it and tell me what to type here.

[00:07:02]Enter the answer. Tell me what will be the answer. Force when a thermodynamic system is taken through a cyclic process. A B C A B C A B C A B C A B C A B C A work. If a thermodynamic system is taken through a cyclic process, what is the work done?

[00:07:31]Viraj, tell me quickly. Are the answers correct? 3.

[00:07:45]Prasad said by Viraj.

[00:07:47]300 is saying good something different answer has come now MHT CT Aspirant 600 and Manisha Bharaskar minus 300 Vaishnavi Lokhande 600 okay simple question here do not make mistake you want to calculate the area of ​​this cyclic process area of ​​the cycle area of ​​the toggle bar clock told you but if it is a clockwise cycle then work positive anti clockwise cycle will work negative this is clockwise positive answer is coming now how much is the base to calculate this area of ​​triangle two to five two to five many people take five for it two to five two to five what is the length is three and here BC height is 100 to 300 what is the height 200 is base three height 200 half in base in height answer 300 j 300 j correct positive will come right simple right If you make a mistake in such a question, what should you do? This is also numerical. 21 January 2026. This year's question is Tell Me the Answer Correct. Harshvardhan Prateek is correct.

[00:09:52]And an important note. Next Monday, we will be giving a marathon lecture on the topic Motion in Plain Class.

[00:10:11]Many of you are still in class.

[00:10:14]But we have to do Class. 1 for December CET.

[00:10:19]So, we have to start preparing for it. Side by side. This lesson is complete. I will take three, four, three hours, four hours. As much time as it takes, I will teach you the question concept in full detail. Question concept. Question concept. Question concept. It will be a big lecture. I will teach you that as the first time you are learning, it will be more conceptual teaching.

[00:10:44]300 Aadish Aadish Sadesh. Two answers come separately. Prasad Prateek Sadesh. And 3dash why is it a die tomic gas h j of work wn expad iobaricly iobaricly hit gwan to it hit given to it wt is the chapter numbers chapter number three of classle ok chapter is big? He converted it to English because the chapter is big, so I thought the chapter number is small, okay, and so on, but now you will find it easy, if it is in the middle, then why did n't the rest get it?

[00:11:48]Yes, Viraj is skilled, why did you also put the symbol, isobaric, if the pressure is constant, if the pressure is constant, how would the division be? Do you know how the division is diatomic, sa by pa means seven five two, if there is no division, then if this square is sh, how much will it be? Question mark, question mark, we have to remove this, divide by two, ba sa ba k ba sa sa sa 100 ba do 7sh ba do 3dash, right 3dash, correct answer, very good, today it was a little slow, why are you so good, why is it like this? Let's tell you quickly, but the questions are not really difficult questions. We took the questions that were solved according to the CT syllabus. But there were many questions that required a different concept or were very complicated. These are not difficult questions. We basically need to get the right answers. We solve CT PY Q Target CT PY Q Target.

[00:13:02]We develop a mentality of solving one type of question and if we find a new question in CT, we go blank. Therefore, we took such questions to practice a little.

[00:13:12]This is also the same. Tell me the answer.

[00:13:16]Sudhir MHT CT Aspirant Prasad Viraj Kushal Everyone says C. C means A for A for Isothermal for Correct.

[00:13:29]Very good. What are the next two?

[00:13:34]Adiabatic Adiabatic is bitter.

[00:13:37]Here is B. Correct.

[00:13:40]Both of them are good. Done, there is no need to check the rest, but to get some knowledge, what is an isobaric? What is an isobaric isocar? It does not work in isocar and the internal energy change in isocar is not zero. Where is the zero? Correct, there is no zero in isobaric. It is also present in isobaric.

[00:14:00]Delta is present. All of them are present. The next question is the sixth. This is a question from the NEET exam. This year, the NEET exam was held.

[00:14:12]Look, do you see the question and can you answer it?

[00:14:22]Today, I have brought 15 questions. I have already started the session a little late. Let's solve it quickly.

[00:14:28]Okay, Viraj has given the answer, but what about the rest? Same answer, different answer, quickly. This is also a cyclic process. It is similar to the first question, only here the triangle is a rectangle. This is even easier.

[00:14:53]Very good, correct answer. Area of ​​the cycle area. Offs Cycles Side His Sideth Si H R Delta Perfect Rit Second Question Another question came up Calculate this answer Tell me the answer Technical Explosion Temperature of One Volume One Mole of Ideal Motmicry Fum 60 F One By Gas In Process By Gas Easy Very So This Year Two Questions Came Up Thermovariti Do These Two Well Solve This Answer In Chat Box I Have Not Set Timer From Next Question Let's Set Timer Okay Take This One Take This One Time It's A Good Question Easy Easy Actually But Should Be Suggested What To Do If Suggested It Will Be Solved Immediately Easily Prasad Prateek Both Delta Viraj D Sabha MHT CET Kushal D Okay Let's Check Everyone's Answer Same Come On Really Everyone Has Given The Answer Most Of The Adiabatic Expansion Adiabatic Adiabatic Processes There Are Many Topics It is simple because K is zero and therefore the sum of delta Y and D is zero. So if someone mistakenly asks for work, then he has to calculate the internal energy and make that internal energy negative.

[00:17:36]How to calculate internal energy, there is only one formula. NC is the delta number of moles. One C is mono. How to calculate Cv? Mono has three degrees of freedom for mono. And the formula for Cv is F. Batu R means Batu R and delta is how much delta 60 P means negative delta.

[00:18:05]NC is the delta delta itself.

[00:18:09]Negative minus the.

[00:18:13]This is your change in internal energy. How much is the change in energy? The change in energy is 30 Ba, 15 R is negative, 15 R is negative, and if you give one more minus, then it will become positive in the work done. So 15 R is positive. This is the answer.

[00:18:31]If you put the value of R in 8.3, You have 15 * 3 = 45 15 * 8 12 + 4 124.5 Correct Perfect Yes Sir Why didn't you use this formula of work?

[00:18:50]You would have got the answer by using the formula AR Delta A One Minus G.

[00:18:56]This formula of work directly. There is no problem but many people do not know it. But I told you the root of internal energy. Okay, not a problem. That is also correct. The formula of work directly is gamma minus one. It is not gamma minus one. The formula of internal energy change is gamma minus one. The formula of internal energy change is formula of work. Mass. Gan. They are both negative of each other.

[00:19:25]Now solve this. I will give you a one- minute easy question. It is a very easy question.

[00:19:30]But let's see if it is right.

[00:19:41]JE usually runs like this. If you go to give the paper of J, there are 25 questions. Which student of J. If you study really well, you can get 45 marks in Physics in CET, in which I think 15 to 17 questions will depend on your luck, but if there are more base questions on your 12th syllabus, you may get 20 questions, but at least 15 questions are answered.

[00:20:17]The answer has not come yet and it has been 53 seconds.

[00:20:28]This is Karnataka CT.

[00:20:33]Prateek has given the answer.

[00:20:45]Kushal Shreyas Khandare.

[00:20:48]Everyone is saying the answer is wrong. But is it really B? Please check it once. Is it really B?

[00:20:56]Check it. Okay. I am the one who says that everyone is still saying that any other answer is okay. I am answering correctly. It has been two minutes. What is the question? The question asked in the question is: Gas taken from state to state B by two different paths. One is gas A. Here is B. This is a state. One state. From this state to this state, it has gone through this path. And when it has gone through this path, it goes through two different paths. Do you remember that when it goes through two different paths?

[00:21:54]Keep the work different because the work path function but the internal energy is the same, that is, when I go to one path or another path, the internal energy will change the same. I cannot say that the work will be the same. No, it may not be. It may not be. Why am I saying that? Because if both the paths are connected, then it will be the same.

[00:22:21]But if there are different paths, then it will be different. But if there are different paths, then it is a problem, but different paths may not be the same.

[00:22:27]I will say that for example, I will show you that different paths do not need different classes. I will show you that if I go from one point to another point or I will show you a P diagram. You will understand a little more.

[00:22:40]I went from one point to another point and went along such a path. Okay, so the area under this will be the same. Right, right? I mean, the area I lost here is the same. I have gained so much here, so the work of both the paths is the same but there is no need for it to be the same every time. Two different paths can have two different works.

[00:23:11]Okay, two same works can also have two works. But there is no guarantee, but what is the guarantee? The internal energy will change the same.

[00:23:16]You can change the internal energy of any path. The internal energy will change the same in different paths. But there is no internal energy here. The internal energy is indirectly given by doubling the mass.

[00:23:29]So the answer is B. Do you understand?

[00:23:34]Good question number nine. Now this is the hardest question. This is the question of CET. You should have solved the question of CT. Let's see if you can do it.

[00:23:47]I will give you three minutes. Three minutes.

[00:23:48]Some people must have solved it. So you will know the answer directly.

[00:23:53]But this is what it is. Let's zoom in a little.

[00:23:56]I have two adiabatic and two isothermals. Is it written as JT1T2 or is it isothermal? Is it written as T1T2? Is it isothermal?

[00:24:17]Isothermals are and green which are green are adiabetics in adiabetics and in isothermal I have colored green and yellow as blue by mistake I said isothermal green adiabetics asked what is volume of B and volume of A question volume of B and volume of A and in what should I find the answer volume of C and volume of D oh I mean I want to find the answer in volume I just want to compare the ratios of the volumes you are ok I just want to compare the volumes this is a CET question this question you did not see in 26 you did not see in 25 you did not see in 24 this is in 22 we found it so I took it here this is different a little bit left but 22 was also easy this is a little bit different the question itself is different such a question is not asked normally never answer delta as it is called beta symbol beta skilled delta shreyas How to do Delta Answers? It's been three minutes. If you get a question like this in CET, first skip it. Don't give three minutes to one question. Don't skip it. Do n't leave it. When the whole paper is over, it means that the PC is complete.

[00:26:50]Come back and revisit it. And then at the end, there will be only one question and the timer.

[00:26:56]You have two or three minutes on it.

[00:26:58]Give it the full time and solve it. But when you are solving and find that in the middle, giving three or four minutes is not recommended at all.

[00:27:07]Okay, okay. Now let's try. I haven't solved the question for a long time. Let's see what can be done. Let's try. Do you want to play in volume volume? Do you want to play in volume volume only? Since A and B are isothermal, you know that Pb is equal to Pb. Do you know why Pb is equal to Pb? Why is it because of simple temperature constant?

[00:27:55]And what will happen here? What happened in this process?

[00:27:59]Equal to PC BC Equal to N RT2 Energy Now by solving this, what do we need to figure out? What is the ratio of A and B? What is the ratio of A and B? What is the ratio of volume B and volume A? What is the ratio of volume A in terms of C and D? What is the gas? It is not given that we can figure out the Gamma etc. It is an adiabatic process but B and C. So when we come from here to here, what will happen when we come from here to here, from here to this point, when I come from here to this point, can I use the Adiabatic rule in this process? What is the temperature of one volume B? I applied it here. The temperature here is Gamma minus one. What will be equal to what will be equal to what will be equal to the temperature here is the temperature here is volume C Gamma. Will it be minus or not?

[00:29:24]Now we got the temperature ratio too. We got this too but the ratio but we don't know how much is the ratio. No, nothing. Nothing.

[00:29:41]Okay. Let's do some work out. We have to think. We have to think.

[00:29:48]Okay. We don't have any options. Let's think. Sometimes, we do n't have time. What else do you say? Sir.

[00:29:57]What is the dimension? There will be no work out. It's a question of ratio. Why do n't we do anything?

[00:30:04]So b / a vb by va equals to p by pbi p ba p ba pbdi and if we multiply these two, we get AC. I made a mistake here.

[00:31:08]pa ba pdi PD should be written. PD.

[00:31:12]Okay. Let's multiply both of them. I will solve it first. Then I will tell you. Padi pc = VD VC/ / vb - 1. And who is this now? PA/ PA / PB Let's do something. Wait, wait. I have been given the same gas to do a job. What is the same gas heart?

[00:31:53]Same gas. This is a cycle, the same gas is the same gas, the current in the cycle is that gas, we do not know if it is a proof, but we do it, we take the high temperature pass, we take the low temperature, we take the exact hit, its formula is the same, we also do the proof, because there is zero in this process, there is no hit, here the hit is exact, there is a hit, there is no hit, here the hit is released, there is a rate, I am going to delete all this, I am going to delete all this, let's try again, but not now, okay, what should we do first, the question is not working, let's go ahead for a while, come back, first, this is again, this is the area of ​​​​tangle, the formula for work done, but it does not work here, I will ask here, the change in internal energy from A to C, this question is of when, it stopped, nothing happened, this question is also a question Is this a CT question?

[00:34:10]In that case, we will see how to do it later. I will take it in tomorrow's lecture. There is no lecture tomorrow. It is Saturday. But can you try?

[00:34:21]Answer this very quickly? This is a question of CT. A to B B to C 30 h. Work done from A to B B to C 30 h. A to B B to C 30 h. Now the topic is that in A to B and B to C, the same information is given. B to C does not work. So A to B works and how much work is done by A to B.

[00:34:48]30 h. Okay, here, work done 30 h. Work done here.

[00:34:55]Now, 68 h of heat is given to the system.

[00:35:02]6 h of heat is given to the system. That is, 68 h of heat is given to A to B. When A to C is going, work is done.

[00:35:14]How much internal energy change will there be? What is the question?

[00:35:27]The work done by the system in going? Okay, work done by the system in going. To B and B to C 30 J of gun to the system Change in internal energy of system between these values ​​is not given This question is incomplete Something is wrong Answer does not match Answer does not match Three options are same Three options are same 3 J 3 J actually but options are wrong There is something wrong in the question itself There is a mistake here 3 should have been given because if work given Change in work given K given then 68 E Delta Pd This logic is 30 or minus then 34 A 38 should have been given Did they do that all three options 55 or there is some mistake here I just looked at the question But this option will be seen I have the wrong question Well this is directly I had to derive it for you Didn't I tell you what is the difference between alpha and eta between Carnot's engine and refrigerator Are you in a relationship? Here I will tell you directly what will be the answer to the relationship between Co of Performance and IT.

[00:36:59]Very good, very good. The answer is the efficiency of this engine. One plus one. Alpha.

[00:37:08]Alpha. Co of Performance. Co of Performance.

[00:37:12]Co. is perfect.

[00:37:19]12 next questions. Another question of 2025 CET 2025. Yesterday, I solved 206 questions, but there was no such question. So I took this. So I took this. Solve it.

[00:37:31]What will come out?

[00:37:35]Check the answer and tell me if this was done. What are you talking about?

[00:37:48]Okay, the last one was this, the last one was this, the one that came in 26, whose option is Vaishnavi Lokhande option, I think this is the question of Vaishnavi, the last one says, tell me what the answer will be, tell me what the answer will be, two cylinders A and B are fitted with pistons containing an equal amount of ideal atomic gas temperature, can the piston of the cylinder be free of a fixed cylinder, do you remember that you have done it many times, tell me, did you do it many times, tell me, answer OK, C, he said, C, okay, for those who have not done it, what is the problem, these two gases A and B are the same piston, fixed piston, movable piston, movable piston, as pressure constant and fixed piston as volume constant, that is, this is an isobaric and this isochoric process, remember that in an isochoric process, all the heat goes into the N-C delta, in an isobaric process, all the heat goes into the N-C delta, in an isobaric process, all the heat goes into the N-C delta, there is no N-C delta. What goes into N C delta? What goes into N C delta? It goes into N C delta. It goes into C delta. It goes into C delta.

[00:39:28]You say, you gave both the same amount of heat. You gave both the same amount of heat.

[00:39:37]If the rise of temperature in A is delta T and in B is delta B, then what will be their ratio? Okay, I asked, let's ask delta B. Divide this. It is equal. One A went here. It will come I should have drawn the lines, now I do n't see any confusion here, I want to show that the origin is moving, this is the origin, it is moving, okay, so I draw it like this, did both the origins move, now tell me how to solve this, first look carefully, this is not a PB graph, this is a PT graph, remember it is not a PV graph, should I put a poll, why is it putting a poll, tell me what is the answer, the same question number, question number A B C and A B CD, tell me what answer will come, maximum students, I have marked option C C, I see maximum in it, I get A C, all four options are coming, Prasad is saying, solve the question, then show me the problem, the only problem is that you need to be able to interpret this question, this question is very easy for those who can interpret graphs, just look at the question, tell me what is the process in this question, three Four Process Three Four Process Constant Pressure Pressure Axis Iobaric and One Two Process What One Two Iobaric But to the Process What to the Process If the Temperature vs. Pressure Graph is a Straight Line Passing the Origin It Has to Be Constant Volume It Has to Be Constant Volume So Here Constant Iobaric is Iobaric and This is Also Who is Iobaric So If Work is Done Where By Chance Then It Will Not Be Done in These Two Processes Work Will Only Happen Here Iobaric Will Happen Here Iobaric and Iobaric Work What Would Be A R Delta What Would Be Work A Delta So Whatever Work Will Happen in Three to Four Will Happen A R Delta That Is T Fo MassT3 Will Be Like This You Will Know That Kati Fo MassT3 Will Be And Whatever Work Will Happen in One Will Happen in One Then It Will Be ErT2 MassT2 MassT1 Do You Know That Work Done Iobaric You need to know that there is an air delta in the air delta.

[00:44:21]You are right. There will be work in the air delta in the fo and there will be work in the in the in. There can be no work in the in. The graph is good. Now you should be able to calculate only the number of moles. Divide these numbers by six. The result will be 400. 2400 by the s.t.2. The s.t.3. The s.t.4. The s.t.5. The s.t.6. The s.t.7. The s.t.8. The s.t.8. The s.t.1. The s.t.1. The s.t.1. The s.t.2 Sosh very good very good the lowest percentage is A the lowest percentage is maximum C I did not make any calculation mistake again once again divide by six 400 divided by three divided by 800 divided by two bash and one divided by 2400 equals a delta date taken on both sides 4 months to do the final minus initial sohe minus bash mass 24 and hereto minus one to do mass point is correct sir a correct a correct correct correct very good who did it well there is no problem let's do the remaining two or three questions and that too one left our carnot let's do it first this has also come up many times but this has not come up in recent years so I thought that some people have not solved this it seems to be an additional issue the rest is a very easy question seems to be four lines The question is, "Read it, it's difficult for those who are reading it for the first time, but those who know the answer know what it is."

[00:46:47]Very good answer. I asked you the temperature ratio of a monoatomic ideal gas.

[00:46:55]Initially its temperature is T1.

[00:46:59]Close in such a cylinder volume.

[00:47:04]How is the volume given? Area of ​​the base in the cylinder. So what is the volume? Now how can it be expanded adiabatically? If adiabatic expansion is done, then the same temperature becomes T2. Due to expansion, if the temperature becomes T2, then the volume will also become 2.

[00:47:25]But the area will not change. The cylinder area is not expanded. The volume changes due to expansion. So now what will be the new volume? And I asked you what is the relationship between temperature and volume. Volume is not expanded.

[00:47:41]What is the relationship between mass and volume?

[00:47:46]Mass is constant. So I can write as t and v1 = v2 = r and g = mass constant. But I don't know the actual area. Because of the past, sov bati2 will be sorry bati2 elv ba l2 re g mass is how much is mono mono mono means f bath massv means bath cons constant constant right na m so this will go beyond tart2 bativ equal what will comet2 bati1t2 bati1 will comet2 bati1 will come this will be equal and this will be one beyond heti mass where there were constants then I can write as1-w oh mav no and this will go beyond na then will go upt1 will go down bav option c very good c is correct c is correct na re t2 ba t1 asked then t2 ba t1 la l1 above l2 will come down found out good let's do the last question and after this it is your wala ha CT 2025 question tell me what to do second last means 15th but after this should he also do one because what will his answer come and how many correct were 15 madhans you got tell me finally three Sample X was of the same gas of the same volume temperature volume of the sample double there are three samples volume double banana two bananas ok so the first process was not it was isothermal in isothermal process if pressure is p volume if volume is double then pressure directly gets halved gets halved gets p constant second was isobaric second was adiabatic what will happen to adiabatic do you know that p re this p re constant came down this p re gamma constant down then volume got double pressure p or gamma here as p was constant if volume got double pressure got halved then volume got double then pressure becomes p and third isobaric here pressure remains p you think ratio of initial pressure final pressure equal ok reverse question final pressure is same what will be initial pressure final pressure are equal so graph will go like this isobaric Isothermal and adiabatic Where will adiabatic go? Adiabatic goes up. So this is P. So what will be the final pressure? What will be the final pressure? Let's ask them all. They all meet at the same point. So what will be their initial pressure? Let's assume that everyone has the same initial pressure. If the initial pressure is P, the pressure of the volume doubles.

[00:51:27]Before the volume was, how much will it be when going backwards? The volume is half the pressure. Double the isobaric pressure. Isothermal and adiabatic pressure. How much will be the pressure in the ratio of the first isothermal and the second is adiabatic? The third isobaric pressure. What is the ratio of the pressure in the isobaric pressure? Which option is the first? The second is the gas pressure. So the gas pressure Iothermal and asked that Wt is the ratio of By B B Ba Consider the volume here A the volume here and in terms of C and D the volume asked so the ratio of these two volumes of these two volumes is asked and the answer is given in terms of these two volumes Look we have to come from this line to this line This is the requirement to come from this line to this line What is the temperature given to us What is the volume then tell me how will the volume and temperature be related when coming to A To D Tv v Re Gamma minus one equals the temperature T2 B Re Mass Where can I use this equation I used on the red line This Io is adiabatic In adiabatic I can use this formula The temperature here is the volume here Re Gamma minus one Here is the temperature here The volume here is not here Ray G Mass is okay, let's try it with BC. Let's take A Ba H. Now I'll use B. Now I'll use A Ba B. I'll use it here again. Temperature B. Now we'll get it. Direct division is the same as pressure.

[00:54:31]Pressure is not complicated. Pressure is not introduced. We should do TV. So, when we come here, what is the formula for adiabatic? Temperature one volume of B. Ray Ga minus one temperature to volume of C. Divide the equation by 2. Everyone lost. Everyone lost.

[00:54:59]Everyone lost. We took the root of mass. Mass one. I'm going to go. If you reverse the equation, the answer will be B. Do you understand? So, what happens normally?

[00:55:21]This question is a question that I have solved many times. I am from 202. The question of 2022 means I have solved the 2023 batch, the 2024 batch, the 2025 batch, the 2026 batch and I am solving the 2027 batch and yet sometimes the first step of what to do in a question does not click and this question is such that you need to know how to do it. So sometimes even if you have solved the question many times, it will happen in CET that you will go blank. You will not understand what it is. So it is not suggested that it is easy to move forward immediately. The first target is in the second lot. In the second lot, you may have left 15 in the first lot.

[00:56:01]In the second lot, those 15th questions are collected and then the really difficult seven or eight questions remain in the last round. Then I can think about them comfortably one by one. If I had done this question, then when I said, come on. Let's go ahead, at that time, I thought, let's keep thinking about this, then maybe B would have gone another minute and I would n't have clicked. This step is the step that I tried. If you see, I was trying B and C, but I clicked something that I had to do between these two, not between these two. That click must be there. It has to be there. I have to give it time.

[00:56:35]Okay, sometimes I don't get the question.

[00:56:38]Skupat come back, tell me what the score is out of f. This is a lot of questions. Isn't it right? Viraj is not tomorrow. Viraj is tomorrow Saturday. I wo n't take it tomorrow. Mandela Monday.

[00:56:56]Monday.

[00:56:58]Marathon lecture. Mandela is a marathon lecture.

[00:57:05]Motion in a plane. The topic of 11th is very good.

[00:57:09]Kushal Prasad. Prateek Chavan. It was a great question. Look, four or five questions were very cool, which were especially good.

[00:57:20]One or two were good in NEET.

[00:57:26]Whatever lecture it is, Mandela, I am planning to start it in the evening at 13:30. I will also make those who do live lectures daily sit in this. You will also tell those who are sitting in the classroom. Those who have been taught this topic in the classroom, if anyone wants to sit, you can sit.

[00:57:46]Mandelath is not Mandelath, I will not take the topic.

[00:57:52]Oh, but even if you have it, I will take it.

[00:57:54]So, I am taking this topic.

[00:58:02]Yes, Prasad. Today, I will upload the assignment sheet of 50 questions of KTG and thermodynamics.

[00:58:08]You solve it. Okay, let's meet Mandelath directly. Now, I will keep uploading the rest of the videos.

[00:58:19]Good night.