DAY 7 : RQ SERIES - PRELIMS | ARITHMETIC SUMS | BANKING & INSURANCE

[00:00:04]Hi everyone, this is Sadina. Welcome to coins. So application guys daily because notific ification ra Monday, Wednesday, Friday series prelims, Tuesday and uh Thursday, Saturday.

[00:01:04]Fore data interpretation 100 B is 20% more efficient than okay and 20% that is 5% 20% by B6 C is 33 1 by3 less effic percent less efficient than 33.33% that is 6 A can complete a work in K days.

[00:02:40]If they all work together can complete a work in days.

[00:02:47]Then find 25% 25% days of simple first step 15. So 15 into 15 One time 24 days value 25.

[00:03:45]So 24 days. So option. Okay. So option B. Yes. Option B 6 days.

[00:04:25]Okay.

[00:04:28]The average runs by a player in seven matches was 89.

[00:04:38]Average 89. After adding the scores of the eighth and nth match up, ethatch natch average runs increased by three. Total match after nine matches the score is increased by threeatches.

[00:05:16]92. Okay. If the eighth match score three runs more than the ninth match natch then find the score score of very simple increasement.

[00:05:43]Incremental 2 into 92 184 2 eth math score plus nth math score additional scoreatch match natch score.

[00:06:43]If eighth match score three runs more than natch xus 2x = Option B4 is the right answer. Okay. Is it clear? Next question.

[00:07:26]Second question.

[00:07:28]The speed of the current is 5 kilome.

[00:07:31]The speed of the boat in still water is five times the speed of the stream.

[00:07:36]Speed of the stream or speed of the current.

[00:07:40]Speed of boat in still water.

[00:07:44]So 5 into 5= to 25 kilome.

[00:07:48]Okay. Yes. And the speed of the car is 20% more than that of water.

[00:07:59]Car 20% 20% 2.5. So 20% five.

[00:08:13]Okay. Next. Then find the time taken by him to travel 180 km by his car and 75 km in still water.

[00:08:24]180 km total. So total time is equal to what?

[00:08:34]Distance by speed. time for so first t1 and t2 first 180 km distance 180 km first time next 3 hours. So total 9 hours is the right answer. So yeah, very simple. Next question. Third question.

[00:09:15]Next. Compound interest. Rame borrowed sum of money from a bank at a compound interest at a rate of 12% peranom. Total amount received after 2 years 6272. Then find twice the 25% of principle. Twice the 25% of principle. 25% of principal fraction.

[00:09:59]So 12 by 100 simplifi 625 784 28 784 overall principle ratio amount ratio in the amount value 672 784 value 6272 6272 784 62721 78400 700 7 * 14 4,900 8 * 14 5,600 5,600 93 cancel 784 8 627 784 into 8 65 into 8 62 5,000 8 4800 25 So 5,000 Okay. Amount twice the 25% of principal. 25% of principle two times 50% of the principal 50% value 2500 is the right answer.

[00:12:11]Option A is the right answer. Okay. Next question. Next question.

[00:12:31]Okay. Next.

[00:12:34]Two trains B and G are running on parallel tracks in the same direction at speed of 60 km per hour, 42.

[00:12:47]60. Yes. 60 km.

[00:12:52]42 kmh.

[00:12:55]Same moving speed. Relative speed.

[00:13:10]18.

[00:13:15]Okay. Next. The length of train B is W + 50 m in the wheel train length W + 50 m.

[00:13:23]Other way G train length W + 100 m.

[00:13:27]Okay.

[00:13:28]If the faster train overtakes the slow train in 110 seconds then find the value of W. So time is equal to what? Distance by speed.

[00:13:40]Okay. Distance by speed is equal to time.

[00:14:00]W + 50 W +en distance. Okay. Relative speed two moving object same kilomet into 5 by 18 5 Okay. W + W 2 W 15. Okay.

[00:14:55]55 2 Wal 150 minus 400. Wal 200. Answer option D is the right answer. Okay, 200 is the right answer. Is it clear? Next question. So, okay. Next.

[00:15:23]Next topic. The ratio of radius of the circle to the side of the square is 7 is to 81.

[00:15:32]Square root of 81.

[00:15:34]Radius side of square root.

[00:15:43]If the area of the circle is 616 cm square area, find the difference between the area of the square and perimeter ofime square.

[00:16:12]616mm area. Okay.

[00:16:22]R² 7 X into 7 X R² 61 R² 49 into 7 into 7 11 3 0 8 2 * 8 * again x right into side of a square= 18 area difference between area and perimeter Okay. Area 4 a square sorry 4 a square a into a so 18 into 18 that is 18 square 184.

[00:17:48]So 24 * 14 72 so 6 34 - 72 252 options opt first 18 square but 18 square - 72. So option A 400 - 1 square 399 6 - 6 2 15 square 16 square 256 256 4us 252.

[00:18:42]So option E is the right answer.

[00:18:45]Okay. Next.

[00:18:48]Next question. The ratio of percentage of Jatin and Raj is 4 to 3.

[00:18:56]Ratio. So J and R 4 to 3 4.

[00:19:03]If the sum of ages of ages of Rajan after 3 years and Jatin before 2 years is 57 age after 3 years.

[00:19:18]Okay. and before 2 years age 4xus 2 after years.

[00:19:33]Okay. Then find the total ages of yes.

[00:19:49]So 56.

[00:19:52]So that total.

[00:20:01]So 4 into 8 4 age 32.

[00:20:09]So final question percentage percentage plus 13 plus 2.5 years after yes age after 2.5 years 24 age 32.5 is the right answer option C is the right answer is it clear next income expend.

[00:20:44]So just income expend.

[00:20:54]Chocolate expendure problem.

[00:21:20]The ratio of income of A and B is 5 is to 6. First income ratio income ratio 5 is to 6 A and B. Okay. And expendure ratio 9 is to roo<unk> 16 4,800 4,800.

[00:21:55]Okay.

[00:22:03]18. Okay.

[00:22:07]Okay.

[00:22:12]Same ratio just sorry 4 into 4,800 3 into 4,800 difference and difference two part Two part 4 into 4,800 into 4800 4800 same value 4 into 4800 3 into 4800 4800 4800 2x 2x value 4,800.

[00:23:10]So x value 2,400 income and expense value income income and expense. Sorry, really sorry.

[00:23:47]value of 2,400 A into 2,400. So A is equal to 12,000.

[00:24:01]Okay.

[00:24:03]B value six part five part value 12,000. Six part value 2,400.

[00:24:11]So 14,400.

[00:24:13]So income 14,400. So incomeav 4,800 in the method only to find income value.

[00:24:34]expend into A and B.

[00:24:48]Find the difference between income of A and C. A and C are if income of C is,600 more than B. B,600 600 15,000. So 16,000. So C in 16,000 A in 12,000 C income 16,000 difference 4,000 difference option A. Okay.

[00:25:18]Very simple. Next question. A shopkeeper sold an article at a profit of L percentage. Had he sold it? Had he sold had he sold it for rupees 140 more he would have gained 2 L minus 8% if the cost price of the article is 2,000 find the value of 2 CP 200% He sold it for 140 more selling price 140% price of profit 2% profit and the difference 140 rupees for example second 150 50% value 150. Okay.

[00:27:18]140% Okay.

[00:27:30]2004 140 140.

[00:27:37]Okay.

[00:27:39]8% 140= 140= 300 value 15 option B is the right Is it clear 140? So 200.

[00:28:19]Next question. Next question. Number system. If the sum of square of two numbers is 89. Sum of square of two numbers.

[00:28:30]X square number Y square 89. Okay. If sum of is X + Y sum of the two numbers then find the product of these numbers.

[00:28:46]So x + yal formula x + y the whole square the whole square x + y value x² + y square value 18 Okay 9 - 8 - 18 that is 2 x - 80 / 2 that is -40 is the right answer. Option B is the right answer. Is it clear? Very simple. Okay. So next last 17.

[00:29:46]So regular early morning Okay, next.

[00:30:15]Thank you. Bye.