This video demonstrates how to solve a system of radical equations by applying algebraic identities: given √a + √b = 35 and √(a + b) = 25, the solution involves squaring both equations to eliminate radicals, using the identity (x + y)² = x² + y² + 2xy to find a + b = 625 and √(ab) = 300, then using (a - b)² = a² + b² - 2ab to find a - b = ±175, and finally solving the resulting linear system to obtain two solutions: (a, b) = (400, 225) or (a, b) = (225, 400).
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The German Math olympiad problem that 99% of Students Get Wrong | Math Olympiad Mathematics
Added:Hello everyone. You're welcome to solve this nice square root math problem. This is the square root of a plus square root of b. This is equal to 35. Let's call this as equation one. Then we have the square root of a + b. This is equal to 25. We can call this as equation two.
Now the question is what is the value of a? What is the value of b given that a and b these are element of real numbers.
Now let's provide a solution from here from equation two. From equation two which is the square root of a + b this is equal to 25. The first step to do here let square on both sides.
And this means that here we eliminate the square root sign. Therefore we have a + b. This is equal to 25 squar. This is 25 * 25.
And therefore we have a + b. This is equal to 625.
We can call this as equation three.
Let's call this as equation three. Now from equation one, equation one is square roo<unk> of a plus square roo<unk> of b.
This is equal to 35.
The first step to do here let's square on both sides.
So that now we have that square root of a + roo<unk> of b ^ 2. This is in the form of x + y raised ^ of 2 which we can express as x ^ of 2 + y ^ 2 + 2 x y.
Applying this algebraic identity then here we have square roo<unk> of a raised ^ of 2 plus square roo<unk> of b raised to the power of 2 then + 2 multiplying by square root of a * square root of b. This is equal to 35 raised ^ of of 2.
Now let's eliminate the square root sign here. This is a plus again here we have b then + 2 multiplying by square root of a * square root of b. We can express this as an individual square root of a * b.
This is equal to 35 squared and this is 12 25.
Now [clears throat] we have that a + b this is from equation three. Equation 3 which is = 625.
Let's substitute 625 here. We have 625 + 2 *<unk> ab= 12 25.
Now let's take 625 on the right hand side. So that we have to multiply by square root of a this is equal to 12 25 subtract 6 25.
So we have 2 *<unk> a this is = 12 25 - 6 25 and this is equal to 600.
So let's divide on both sides by two.
And what we have here is that square root of a b this is equal to 600 / 2.
This is equal to 300. This is equal to 300.
So we have square root of a this is equal to 300. Now to solve for a let's square on both sides.
And this means that a * b this is equal to 90,000.
Let's call this as equation four. Let's call this as equation four. Now from equation three, from equation 3 which is a + b equal to 625.
Let's square on both sides from here.
So that now a + b ^ 2 this is the same thing as a 2 + b 2 + 2 * a this is equal to 625 raised to the power of 2.
So we have that a 2 + b 2 + 2 * a is equation 4 and this is equal to 90,000.
So let's substitute 90,000 here. This is equal to 625 squared and this is equal to 390,000 625.
So this implies that we have a 2 + b 2 + 90,000 * 2 this is 180,000.
This is equal to 390,625.
Let's take 1 + 198,000 on the right hand side. So that we have a 2 + b 2 this is equal to so we have a² + b² this is equal to 390,625 - 180,000.
And therefore we have a 2 + b² this is equal to we have 390,625 - 190 this is 210, 625. We can call this as equation.
Equation five. Let's call this as equation five. In the next step we have that x subract y to the^ of 2. This can be expressed as x ^ 2 + y ^ 2 subtract 2 x y. This is an algebraic identity. And therefore, if we have a - b raised ^ of 2. This is the same thing as a 2 + b 2 subtract 2 * a b.
Now this means that a subtract bis^ 2 this is equal to a² + b² this is equation 5 as you can see here. So we have 210, 625 subtract 2 multip is equation four and this is the same thing as 90,000.
Now we have a - b ^ of 2. This is equal to 10,000 625 subtract 180,000.
So this is to mean that a subtract b^ of 2 this is equal to 210,625 - 18,000 and this is equal to 30, 625.
To solve for the value of a minus b, let's introduce a square root on both sides. We have the square root of a minus b raised to the power of 2. This is equal to plus or minus the square root of 30,625.
Now let's eliminate the square root on both sides so that we have a minus b.
This is equal to plus or minus the square root of that,625.
This is the same thing as the square root of 175 raised to the power of 2.
And let's eliminate the square root sign here. So that we have a minus b. This is equal to plus or minus 175.
So we have two possible cases here. We have a minus b. This is = 175 [snorts] and we have a minus b this is equal to 175.
Now given that a equation three we have a + b this is = 625 and we have a subtract b this is = 175.
Again here we have a + b this is equal to 625.
and we have a minus b this is equal to 175.
Now from the first set of these are two set of re equations.
Let's sum these two equations here. a + a this is 2 a + b + - b. This cancels out and this is equal to 625 + 175. This is equal to 800.
Now let's divide both sides by two.
And this means that a is equal to 400.
So we have the value of a in case one is equal to 400.
Let's solve for b.
B is equal to 625 subtract a. So we have that b is = 625 subtract a which is 400.
And what we have here we have that B is equal to 625 - 400 and therefore we have 225.
We have the value of B is 225.
So therefore in the first case that is in case one a comma b this is equal to 400 comma 225.
This is the first set of solution. This is the first set of solution. In case two here in case two we have two set of frame equations.
Let's sum these two set of linear equation here. A + A this is 2 A.
We have B + - B. This cancels out 625 + - 175. So this is the same thing as 450.
Let's simplify here. Let's divide both sides by two.
What we have here is that a is equal to 225.
A is = 225.
Let's solve for B. B is = 625 subtract A. So that we have B is equal to 625 subtract A which is 225.
Therefore we have the value of B in case 2 = to 400.
In case two the value of B is 400.
Now the second set of solution here for A, B.
This is equal to 225, 400.
This is the second set of solution that we have.
So kindly follow the steps, like this video and kindly subscribe.
See you in the next video and thank you for watching.
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