Ampere’s Circuital Law Explained | Straight Conductor, Solenoid & Toroid | Class 12 Physics

[00:00:03][music] Hi everyone.

[00:00:19]Last video one by one straight conductor and then circular magnetic field strength and magnetic field.

[00:00:49]So magnetic field explanation.

[00:01:22]one by one. So, so for closed integral B vector dot DL vector equal to mu I enclosed magnetic field to each other.

[00:02:10]Coil straight conductor.

[00:02:15]Straight conductor.

[00:02:29]magnetic field.

[00:02:31]Magnetic field screw represents directions of the current magnet.

[00:02:55]So this will be your dot. This will be your cross. So rad out right. So I just pattern.

[00:03:20]So which mean this is out right in magnetic field out.

[00:03:30]So dot. Okay.

[00:03:56]Magnetic fielding circle direction outward magnetic field circle which Magnet B dot in the dot A vector dot B vector equal = to a cos theta 0° max vector angle 90° Z because cos 0 becomes zero.

[00:05:57]It is a dot product magnetic field and the magnetic field maximum strength.

[00:06:16]You want to run this side.

[00:06:39]magnetic field.

[00:06:41]magnetic field.

[00:06:51]Right.

[00:07:05]Number of deals.

[00:07:09]Obviously, right?

[00:07:32]closed integral B do dl which is equal to mu i enclosed. So the left hand magnetic field right. So magnetic field.

[00:08:03]So your left hand side in the equation says magnetic field and magnetic field length magnetic field and magnetic field.

[00:08:32]circle right in the B, right? DL which is cos theta right closed integral equal to mu right micos magnetic field and the magnetic field.

[00:09:22]So current enclosed this makes an angle 0° B closed integral DL of the magnetic field in a circle. So 0 2 pi r equal to in the mu not I enclosed magnetic field for a straight conductor B which is equal to in the mu not I enclosed upon length integrate upper limit and lower limit 2 r - 0 2 pi This is your magnetic field strength already.

[00:10:24]2 R.

[00:10:31]I think here we have 2 distance.

[00:10:44]Fourth standard. Four five are 20.

[00:10:50]12th Four, five, 5 magnet.

[00:11:33]So magnetic field magnetic field depends upon medium depends upon current and the distance between the distance between and the point and then the wire. So you have to be very cautious.

[00:12:04]magnetic field.

[00:12:15]So solenoid it is exactly magnetic did exactly imagine this is your positive terminal.

[00:13:02]Okay.

[00:13:04]Negative terminal magnetic field.

[00:13:36]Hint magnet magnetic field.

[00:13:53]Sorry. Magnetic field.

[00:13:57]Magnetic field because we know and pole sorry closed integral right m I enclosed I'll make it little Bit shorter concept B C A B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B B C C D A single conductor A magnetic field.

[00:15:29]So they both are parallel to each other which makes an angle 0° B which makes an angle 90° A current which magnet which makes an angle 90° A to B A to B. So A to B C D 90°.

[00:16:33]So finally mu I enclosed it makes an angle closed integral A to B b DL cos theta equal to muenalgen Total B 0 to L sub which is equal to mu I enclosed.

[00:17:35]foreign number of most of the students confuse capital total number of turns in that solenoid capital total Total terms capital N small equal to capital N upon length total number of turns particular for example.

[00:18:34]Okay.

[00:18:56]number of capital number of small. So total number of turns in the solenite total number of turns in that particular length different total length I can simply write as capital N= mu I enclosed capital N Yellow in the yellow mu n I enclosed magnetic field strength mu ieng Spring.

[00:20:20]Correct.

[00:20:26]magnetic field.

[00:20:29]So in the magnetic field this is the length which is your magnetic different conditions as we discussed in on the surface outside because it is a closed pattern closed integral of BL Okay. B. DL equal to M I enclosed.

[00:21:53]in the case magnet.

[00:22:05]So that is zero.

[00:22:19]Outside zero.

[00:22:22]Outside zero. Inside zero.

[00:22:44]I'm not going to change anything.

[00:22:48]integral of dl equal to mu i enclosed.

[00:22:58]Okay.

[00:23:08]So you took that as you took as 0 to 10 to 15 seconds.

[00:23:23]10 9 8 7 6 5 4 3 2 1 level. So the circle 0 to 2 r 2 which is equal to length total mu i enclosed. So number of small l 2 pi r. So 2 pi r 2 cancel. So b is nothing but mu n i closed.

[00:24:26]So magnetic field comment section.

[00:24:59]Thank you. Help this with a smile.